1●√x/√x-1
1●ctg(x+1) |f(x)=ln sin(x+1)|
1●[0;+∞) |√õ>–1|
1●2√x•(1/3x+1)+C |u(x)=x+1/√x|
1●2πn,n*Z
1●{x=(–1)k•arcsina+kπ, k*Z} {|a|≤1 {sinx=a
1●óðàâí íå èìååò ðåøåíèè {|à|>1 {sinx=a
1●x={±arccosa+2kπ,k*Z {|a|≤1 {cosx=a
1● óðàâí íå èìååò ðåøåíèè {|a|>1 {cosx=a
1●x={arctga+kπ,k*Z {tgx=a
1●x={arcctga+kπ,k*Z {ctgx=a
1●1 |1–sin α cosα tgα|
1●(–∞;-1]U[1;+∞) {|x|≥1
1●(–∞;-1]U[1;+∞)
1●(–1;+∞) |ó=loga√x+1|
1●a)-1;1 b)jok c)[-∞;0][0;∞]
1●a)–1;1 á)æîê (–∞;0)(0;∞) |ó=1/õ–õ à)íîëäåðèí á)îñó àðàëûãû ñ)êåìó àðàëûãûí òàáûíûç|