2●π/2(2π+1) n*Z(–1)k π/6+πk,k*Z ( cosx=sin2x )
2●π/2+2πn; (–1)n+1π/6+πn; {cos2x=sin(π+x)
2●π/4+2πn, n*z |sinx+cosx=√2|
2●π+2πn; n*z |cos(π+x)=sinπ/2|
2●π+πn,n*Z
2●2xcos²
2●πn, n*Z; ±π3+2πê |sin2x=sinx|
2●πn/2≤x<π/4+πn/2,n*Z | ó=√tg2x|
2●πn≤x<π/2+πn,n*Z |y=√sin2x/cosx|
2●õ=πn, õ=–π/2+2πn... |f(x)=sin2x +sinx |
2●õ=±π/3+2πê, ê*Z |f(x)=sinx-x/2|
2●õ=0; õ=π/2+πê |f(x)=xsinx+cosx|
2●2x+sin2x/4+Ñ |f(x)=cos²x|
2●õ=4 |ó=√2 è ó=2|
2●b=π–2a/2